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本文始自林夕成_MC_Wang发布于19年9月。本文作者对代码进行了优化,使其符合题目要求
花果山总共有n只猴子,猴子们确定通过以下方法选择大王:所有猴子从0到n-1进行编号,按照顺序围成一圈;
从0号开始,每隔m只猴子会依次连续淘汰k只猴,淘汰的猴会出圈(例如,最开始0到m-k-1号会被保留,m-k到m-1
号淘汰,m到2m-k-1号保留,2m-k到2m-1号淘汰,以此类推);最后剩下1只猴未被淘汰,那只猴将会成为大王。
输入描述:
每组输入包括3个整数n,m,k其中1<=n<=1000000, k<m。
输出描述:
输出只有一行,包含一个整数,表示美猴王的号码。
示例:
输入:10 3 2
输出:6
#include <stdio.h> #include <malloc.h> typedef struct node{ int data; struct node *prior; struct node *next; }looplist; looplist* double_looplist_create() { looplist *h = (looplist *)malloc(sizeof(looplist)); h->next = h; h->prior = h; return h; } void looplist_insert_head(looplist *h,int value) { looplist *temp = (looplist *)malloc(sizeof(looplist)); temp->data = value; if(h->next == h) { temp->next = h; temp->prior = h; h->next = temp; h->prior = temp; } else { temp->next = h->next; temp->prior = h; h->next->prior = temp; h->next = temp; } } looplist * looplist_cut_head(looplist *h) { looplist *temp = h; while(h->next != temp) { h = h->next; } temp->next->prior = h; h->next = temp->next; free(temp); temp = NULL; return h->next; } void looplist_show(looplist* h) { looplist *p = h; do { printf("%d\t ",p->data); p = p->next; } while(p != h); putchar(10); } void monkey_king(int n,int m,int k) { looplist *h = double_looplist_create(); looplist *temp = NULL; int i; for(i = n-1;i>=0;i--) { looplist_insert_head(h,i); } h = looplist_cut_head(h); while(h->next != h) { looplist_show(h); printf("\n"); for(i = 1;i<= m;i++) { h =h->next; } for(i = 1;i<=k;i++) { if(h->prior != h) { temp = h->prior; h->prior = temp->prior; temp->prior->next = h; free(temp); temp = NULL; } else break; } } printf("the monkey king is%d\n",h->data); free(h); h = NULL; } int main() { int n,m,k; printf("请输入参数:\n"); scanf("%d %d %d",&n,&m,&k); if(n<1||n>99999||k>=n||k<1) { printf("输入参数有误\n"); return -1; } else if(n==1) { printf("the monkey king is number:%d",n-1); return 0; } else { monkey_king(n,m,k); return 0; } }
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