C++实现爱心_gcc爱心源代码

引言：

        最近看很多人都在玩这个爱心。

下面程序可以直接跑，快去和你学计算机的女友表白吧。

程序实现：

#include<stdio.h>
#include<math.h>
#include<windows.h>
#include<tchar.h>
#define _UNICODE _UNICODE
 
float f(float x,float y,float z)
{
	float a =x*x+9.0/4.0*y*y+z*z-1;
	return a*a*a-x*x*z*z*z-9.0/80.0*y*y*z*z*z;
}
float h(float x,float z)
{
	for(float y=1.0; y>=0.0; y-=0.001)
	    if(f(x,y,z)<=0.0)
	        return y;
	return 0.0;
	        
}
int main()
{
	SetConsoleTextAttribute(GetStdHandle(STD_OUTPUT_HANDLE),0x0C);
	HANDLE o = GetStdHandle(STD_OUTPUT_HANDLE);
	_TCHAR buffer[25][80] = { _T(' ') };
	_TCHAR ramp[] = _T(".:-=+*#%@");
	
	int count= 0;
	int count1=0;
	system("color 0c");
	for (float t = 0.0f;; t += 0.1f) {
		int sy = 0;
		float s = sinf(t);
		float a = s * s * s * s * 0.2f;
		
		for (float z = 1.3f; z > -1.2f; z -= 0.1f) {
			_TCHAR* p = &buffer[sy++][0];
			float tz = z * (1.2f - a);
			for (float x = -1.5f; x < 1.5f; x += 0.05f) {
				float tx = x * (1.2f + a);
				float v = f(tx, 0.0f, tz);
				if (v <= 0.0f) {
				    float y0 = h(tx, tz);
				    float ny = 0.01f;
				    float nx = h(tx + ny, tz) - y0;
				    float nz = h(tx, tz + ny) - y0;
				    float nd = 1.0f / sqrtf(nx * nx + ny * ny + nz* nz);
				    float d = (nx + ny - nz) * nd * 0.5f + 0.5f;
				    *p++ = ramp[(int)(d * 5.0f)];
				} else
				    *p++ = ' ';
			}
		}
		for (sy = 0; sy < 25; sy++){
			COORD coord = { 0, sy };
			SetConsoleCursorPosition(o, coord);
			WriteConsole(o, buffer[sy], 79, NULL, 0);
		}
		if(count <= 10) {
			printf("I love You - - - ,Mua~\n") ;
			printf("            By ---");
			count++;
		} else {
			printf("You Are My Best Lover.\n");
			printf("            爱你呦");
			count++;
			if(count>=20) {
				count =0;
			}
			
		}
		Sleep(33);
			}
}

效果图：