Flutter Android 实现 APP跳转_安卓接收第三方app跳转参数

一、APP 实现被打开

创建URL scheme

修改/app/src/mian/AndroidManifest.xml配置

配置  

scheme="xxxxxx"

android:host="xxxxxx"

android:pathPrefix="/xxxxxx"

<intent-filter>
				<action android:name="android.intent.action.VIEW" />
				<category android:name="android.intent.category.DEFAULT" />
				<category android:name="android.intent.category.BROWSABLE" />
				<data android:scheme="demoScheme" android:host="host" android:pathPrefix="/path/subpath" />
</intent-filter>

重新编译APP；

注册完成，APP已经可以被第三方调用了；

二、打开第三方APP

安装插件：url_launcher: ^5.7.10

 launchURL() async {
    const url = 'demoScheme://host/path/subpath';
    if (await canLaunch(url)) {
      // 判断当前手机是否安装某app. 能否正常跳转
      await launch(url);
    } else {
      // 无安装APP
    }
  }

三、接收跳转参数：

String _initialLink;
Uri _initialUri;
  
@override
  void initState() {
    super.initState();
    initPlatformStateForStringUniLinks();
  }
 
  /// 接收跳转数据
  initPlatformStateForStringUniLinks() async {
    getLinksStream().listen((String link) {
      print('got link: $link');
    }, onError: (err) {
      print('got err: $err');
    });
 
    _initialLink = null;
    _initialUri = null;
    try {
      _initialLink = await getInitialLink();
 
      print('initial link: $_initialLink');
      if (_initialLink != null) {
        _initialUri = Uri.parse(_initialLink);
      }
    } on PlatformException {
      _initialLink = null;
      _initialUri = null;
      print('Failed to get initial link.');
    } on FormatException {
      _initialLink = null;
      _initialUri = null;
      print('Failed to parse the initial link as Uri.');
    }
 
    if (!mounted) return;
  }