FastJson之常见序列化特征的使用_writenonstringvalueasstring

简述

Fastjson的序列化特性定义在枚举类com\alibaba\fastjson\serializer\SerializerFeature.java中，目前正好有30项。
可以通过设置多个特性到FastjsonConfig中全局使用，也可以在某个具体的JSON.writeJSONString时作为参数使用。
QuoteFieldNames, //key使用引号
UseSingleQuotes, //使用单引号
WriteMapNullValue, //输出Map的null值
WriteEnumUsingToString, //枚举属性输出toString的结果
WriteEnumUsingName, //枚举数据输出name
UseISO8601DateFormat, //使用日期格式
WriteNullListAsEmpty, //List为空则输出[]
WriteNullStringAsEmpty, //String为空则输出””
WriteNullNumberAsZero, //Number类型为空则输出0
WriteNullBooleanAsFalse, //Boolean类型为空则输出false
SkipTransientField,
SortField, //排序字段
WriteTabAsSpecial,
PrettyFormat, // 格式化JSON缩进
WriteClassName, // 输出类名
DisableCircularReferenceDetect, // 禁止循环引用
WriteSlashAsSpecial, // 对斜杠’/’进行转义
BrowserCompatible,
WriteDateUseDateFormat, // 全局修改日期格式,默认为false。JSON.DEFFAULT_DATE_FORMAT = “yyyy-MM-dd”;JSON.toJSONString(obj, SerializerFeature.WriteDateUseDateFormat);
NotWriteRootClassName,
DisableCheckSpecialChar,
BeanToArray,
WriteNonStringKeyAsString,
NotWriteDefaultValue,
BrowserSecure,
IgnoreNonFieldGetter,
WriteNonStringValueAsString,
IgnoreErrorGetter,
WriteBigDecimalAsPlain,
MapSortField

案例

package fastjsonDemo.JSONDemo.demo1;

import com.alibaba.fastjson.JSON;
import com.alibaba.fastjson.serializer.SerializerFeature;
import fastjsonDemo.JSONDemo.demo1.pojo.User;
import org.junit.Test;

import java.math.BigDecimal;

public class serializePeculiarity {
   static User user;

   static {
      user = new User();
      user.setName("校长");
      user.setAge(3);
      user.setSalary(new BigDecimal("123456789.0123"));
   }


   @Test
   public void ceui() {
      //常规
      String jsonString = JSON.toJSONString(user);
      System.out.println("jsonString = " + jsonString);//{"age":3,"name":"校长","salary":123456789.0123}

      //使用单引号
      String jsonString1 = JSON.toJSONString(user, SerializerFeature.UseSingleQuotes);
      System.out.println("jsonString1 = " + jsonString1);//jsonString1 = {'age':3,'name':'校长','salary':123456789.0123}

      //使用单引号,并且对格式进行缩进
      String jsonString2 = JSON.toJSONString(user, SerializerFeature.UseSingleQuotes, SerializerFeature.PrettyFormat);
      System.out.println("jsonString2 = " + jsonString2);
      /*jsonString2 = {
      'age':3,
      'name':'校长',
      'salary':123456789.0123
      }*/


   }

}
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