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神经,树状数组做多了一开始还想着用树状数组来查询差分数组,但是我们要进行所有元素的查询,直接过一遍就好啦
class Solution { public: int numberOfPoints(vector<vector<int>>& nums) { vector<int> c(105, 0); for (int i = 0; i < nums.size(); i++) { c[nums[i][0]] += 1; c[nums[i][1] + 1] -= 1; } int ans = 0; int num = 0; for (int i = 1; i < 105; i++) { num += c[i]; ans += (num > 0); } return ans; } };
就好像这个题目,我们可以小试牛刀直接进行树状数组
int a[60]; int lowbit(int x) { return x & (-x); } void add(int x, int p) { for (int i = x; i <= 50; i += lowbit(i)) { a[i] += p; } } int query(int x) { int sum = 0; for (int i = x; i; i -= lowbit(i)) { sum += a[i]; }return sum; } class Solution { public: bool isCovered(vector<vector<int>>& ranges, int left, int right) { for (int i = 1; i <= 50; i++) a[i] = 0; for (int i = 0; i < ranges.size(); i++) { add(ranges[i][0], 1); add(ranges[i][1] + 1, -1); } int flag = 1; for (int i = left; i <= right; i++) { int t = query(i); if (!t) { flag = 0; break; } }return flag; } };
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