AtCoder Beginner Contest 196 ----- B(模拟)_given an integer or a decimal xx, round it down to

Problem Statement

Given an integer or a decimal XX, round it down to an integer and print the result.

Constraints

• 0≤X≤101000≤X≤10100
• XX is an integer or a decimal with at most 100100 digits after the decimal point, without unnecessary leading zeros.

Sample Input 1 Copy

5.90

Sample Output 1 Copy

5

We round down 5.905.90 to an integer, 55, and print it as an integer. Non-integer outputs such as 5.0 will be judged as incorrect.

字符串存储

1 0的话直接输出

2 不是0的话找小数点之前的数，加到字符串t种

code:
 

#include<bits/stdc++.h>
#define INF 0x3f3f3f3f
#define N 100003
#define mod 100000
#define pb push_back
#define x first
#define y second
#define ull unsigned long long
#define ll long long
using namespace std;
int a[N];
int main()
{
	ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
    //freopen("in.txt", "r", stdin);
    //freopen("out.txt", "w", stdout);
	string s;
	cin >> s;
	if(s[0] == '0')
	{
		cout << 0 << endl;
		return 0;
	}
	
	string t;
	for(int i = 0;i < s.length();i++)
	{
		if(s[i] != '.')
		t += s[i];
		else 
		break;
	}
	cout << t << endl;
    return 0;
}