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话不多说!
先看小题!!
如下字符串:
String str = “The String class represents character strings. All string literals in Java programs, are implemented as instances of this class. Strings are constant; their values cannot be changed after they are created. String buffers support mutable strings. Because String objects are immutable they can be shared.”;
统计各个字符出现的次数,-----------------并排序!!!
(方法不是唯一的,适合自己的或者更易理解的才是前期学习java的通路)
小解方式一:
使用HashMap或者TreeMap===========================================>>>>>>>>
public void test3(){ String str = "The String class represents character strings. All string literals in Java programs, are implemented as instances of this class. Strings are constant; their values cannot be changed after they are created. String buffers support mutable strings. Because String objects are immutable they can be shared."; //String replace = str.replace(" ", "");//去掉空格,如果不想比较空格/符号之类的可以使用这句代码/后面代码str改为replace char[] chars = str.toCharArray(); //字符出现的次数,排序 Map<Character,Integer> map = new TreeMap<>(); for (int i = 0; i <chars.length ; i++) { if(!map.containsKey(chars[i])){ map.put(chars[i],1);//键值对---key-->出现的字符 }else{ //value-->同个字符出现的次数 map.put(chars[i],map.get(chars[i]) +1); } } List<Map.Entry<Character,Integer>> list = new ArrayList<>(map.entrySet()); Collections.sort(list, new Comparator<Map.Entry<Character, Integer>>() {//使用比较器比较value的大小排序 @Override public int compare(Map.Entry<Character, Integer> o1, Map.Entry<Character, Integer> o2) { return -o1.getValue().compareTo(o2.getValue()); } }); for(Map.Entry<Character,Integer> entry : list){ System.out.println(entry.getKey() + "=" + entry.getValue()); } }

小解方式二:
使用io流:====================================================>>>>>>>>>>>>>>>
public class MyStringTest { @Test public void test1(){ String str = " ai bbiadg 字符 数字 汉字 符合 其他 .'',/';][%%$#@!&*()_+ "; FileWriter fw = null; try { fw = new FileWriter(new File("MyStringTest.txt"));//一步到位,创建字符输出流 fw.write(str.toCharArray());//将字符串写入一个文件 } catch (IOException e) { e.printStackTrace(); } finally { try { if(fw != null) fw.close(); } catch (IOException e) { e.printStackTrace(); } } } @Test public void test2(){ BufferedReader br = null; BufferedWriter bw = null; try { Map<Character,Integer> map = new HashMap<>();//使用Map便于保存 字符--次数 br = new BufferedReader(new FileReader("MyStringTest.txt"));//创建字符输入缓冲流 int len = 0; while ((len = br.read()) != -1){//读取文件中的内容,返回-1表示读取完毕 char ch = (char)len; if(!map.containsKey(map.get(ch))){//统计各个字符出现的次数 map.put(ch,1); }else{ map.put(ch,map.get(ch) + 1); } } bw = new BufferedWriter(new FileWriter("MyStringCount.txt"));//创建字符输出缓冲流 Set<Map.Entry<Character, Integer>> entrySet = map.entrySet(); for(Map.Entry<Character,Integer> entry : entrySet){//增强for遍历集合 switch (entry.getKey()){ case ' ': bw.write("空格=" + entry.getValue());//依次写出key--value break; case '\t': bw.write("tab=" + entry.getValue()); break; case '\r': bw.write("回车=" + entry.getValue()); break; case '\n': bw.write("换行=" + entry.getValue()); break; default: bw.write(entry.getKey() + "=" + entry.getValue()); break; } bw.newLine();//换行操作 } } catch (IOException e) { e.printStackTrace(); } finally { try { if(bw != null){ bw.close(); } } catch (IOException e) { e.printStackTrace(); } try { if(br != null){ br.close(); } } catch (IOException e) { e.printStackTrace(); } } } }

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